Alternative to boolean union to determine many volumes?

Replies to This Discussion

Permalink Reply by Michael Pryor on January 13, 2014 at 6:49am

Looking at your screen in say boolean is the only way. Break it into parts.

Permalink Reply by Danny Boyes on January 13, 2014 at 7:30am

You could use something like Simpson's Rule:

V = h/3(A0 + 4*A1 + 2*A3 + ..... + 4*An-1 + An)

Where h is the interval between section areas (A)

NB n must be odd

This is used to calculate the displacement of ships.

See attached. I have done it for your example but have not applied it to multiple sets as I haven't the time at the moment. Maybe some one else can have a go.

BTW the [UNION] and  [VOLUME] takes a total of  70 ms where the area component takes 4 ms 

Attachments:

• Simpsons Rule.gh, 44 KB

Permalink Reply by Danny Boyes on January 13, 2014 at 7:57am

Correction to the BTW comment I didn't take into account the Intersection and Region Union Components. So in this example they are the same but if you try and ramp up the accuracy by having lots of sections then it is slower.

So this might not be a solution after all

Permalink Reply by Marc on January 13, 2014 at 2:16pm

Thanks for the great replies. I'll try the Simpson's Rule. Maybe it will work better.

Permalink Reply by Danny Boyes on January 13, 2014 at 2:30pm

It doesn't work faster but it might work on all