Conditional Statement

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Permalink Reply by David Rutten on July 22, 2013 at 5:50am

I think the best way to approach this is to always scale the object, but use a scaling factor of 1.0 if the area is between the limits (L0 and L1). The algorithm would thus look like:

1. Measure Area A of shape.
2. Define target area At to be the same as A.
3. If A is smaller than L0 then set At equal to L0.
4. If A is larger than L1 then set At equal to L1.
5. Compute the scaling factor F that is needed to go from A to At.

The scaling factor which changes the area from A to At incidentally is the square-root of the ratio of the two.

--

David Rutten

david@mcneel.com

Tirol, Austria

Attachments:

• scaling.gh, 13 KB

Permalink Reply by Agneesh on July 22, 2013 at 6:34pm

David,

Works great. 

Thank you so much for your help. Especially explaining the logic. Just 1 question, how did you get 

Scaling factor = square-root of the ratio?

thanks

AB

Permalink Reply by David Rutten on July 23, 2013 at 5:23am

Well, scaling factors are basically the same as linear dimensions, i.e. length. Lengths are expressed in meters. Areas are expressed in meters-squared. So when you scale something with a factor 2, the area becomes 4 times bigger (and the volume 8 times as volumes are expressed in meters cubed).

Scaling lengths is quite straight-forward. If you have a curve that has a length of 10m and you want it to have a length of 15, you just divide 15 by 10, giving you 1.5 which is the scaling factor you need.

Since Areas have that square in there, you need to cancel it out by using a square-root. If you wanted to match a specific volume, then you need the cube-root of the ratio.

--

David Rutten

david@mcneel.com

Tirol, Austria

Permalink Reply by Agneesh on July 28, 2013 at 2:49pm

Thank you very much David