Grasshopper

algorithmic modeling for Rhino

I cant for the life of me figure out how to replace a branch of a tree.  

Lets say i have a tree

{0;0} n8

{0;1} n8

{0;2} n8

{0;3} n8

{0;4} n8

{0;5} n8

And i want to alter the data in {0;0} n8 and {0;5} n8 I can easily retrieve a specific tree branch, then modify the data, lets say to each have 6 items in their list instead of 8.  the end resut i want is:

{0;0} n6

{0;1} n8

{0;2} n8

{0;3} n8

{0;4} n8

{0;5} n6

But i cant seem to get the "replace branch" componet to work

In reality i have a tree that consists of 108 branches, so exploding the tree and entwining (which is my normal work around) is impractical

any help is appreciated!

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Replies to This Discussion

ReplaceBranch renames the branch index. If you had a branch {0;0;0} and wanted to have {0;1} instead, this would be your component.

For your problem: you normally have a logic, that is flexible enought to handle zero input. Say you want to delete the first and last item in the list. Then your logic could pass 0 and [listLength-1] in your branches {0;0} and {0;5} and use those for a CullIndex. For branches, you want to leave untouched, just pass no values.

I think i understand what your saying.  But for my specific problem, im not trying to eliminate items in the list, i am taking the {0;0} n8 and completely changing the items in the list.  

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Don´t see a reason why not to use [ReplaceBranch] here. Seems convenient:

Thanks Phillip,  I couldn't figure out how to make that work.

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