Data List Management/Filtering

Replies to This Discussion

Permalink Reply by David Stasiuk on February 25, 2013 at 4:19am

Well...here's a way to start.  I'm not sure exactly what output you're looking for, as splitting these lists out will just give you something like the same values broken into data paths they resemble.  But you can do it...I've added in a little extra here so that you can get the index of the matching pairs from the original lists.

A good way to get those unique matches between two number groups when they are sequential is to use two series components...the first gives you all unique values, and the second steps from each unique value to the end of the list.  This particular definition would be simpler to write in a script, but this works too.

Attachments:

• unique_list_match.gh, 8 KB

Permalink Reply by Mickey Htoo on February 25, 2013 at 6:45pm

Hi David,

You solve the problem all the way. Actually I need the index number together with the pair.

Thank you for your kindness.

Best!!!

Permalink Reply by Mickey Htoo on February 26, 2013 at 11:28pm

Dear David,

Thank you for your help.  I followed all the steps yet cull pattern list is empty (second last steps). Please refer the below jpeg.

I wonder why and couldn't figure it out?  Culling patterns has 61120 values and List to cull has 955 values.  I am still Gh beginner and thank you much for your help.

Best Regards.

 

Permalink Reply by David Stasiuk on February 27, 2013 at 1:01am

no problem!  glad to help you out.  it looks like a really simple little issue...your strings aren't formatted exactly the same...so the ones coming from your set are x & "," & y and the ones from your formula below are x & ", " & y...it's that space after your comma in the second one that's causing them to all come back unequal.

One other thing I'd highly recommend is that you change your settings to display fancy wires...this is super helpful for the rapid identification of item/list/data flow through your definition.

Permalink Reply by Mickey Htoo on February 27, 2013 at 1:17am

Wow, you are the expert!  

Thank you so much for your time and help.

Best Regards.

Permalink Reply by Mickey Htoo on February 25, 2013 at 6:42pm

Thank you for your reply.

Sorry if I didn't verify the problem clearly. Actually I have a list (pair numbers) and I just need to filter out different pairs into individual lists.