Remove N characters form beginning or end of a string

Replies to This Discussion

Permalink Reply by Danny Boyes on May 2, 2012 at 12:47pm

there is a component for spliting a string into individual charaters. then you could shift list -1 andstring join back together again. if you need i can post a demo later

Permalink Reply by David Rutten on May 2, 2012 at 12:56pm

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David Rutten

david@mcneel.com

Poprad, Slovakia

Permalink Reply by Danny Boyes on May 2, 2012 at 1:24pm

thanks david, never thought about using the index cull like that

Permalink Reply by Chris Hanley on May 2, 2012 at 12:58pm

using an f1 component, you could use the formula

Left(x,5)

x being your list of values in x,y,z, format.

Permalink Reply by Danny Boyes on May 2, 2012 at 1:27pm

ideally it should include the string length function -1.

cannot remember if is left(x,length(x)-1) or left(x,len(x)-1)

Permalink Reply by Chris Hanley on May 2, 2012 at 1:51pm

I do like the cull index example!

Permalink Reply by Daniel Bates on May 2, 2012 at 2:09pm

Just want to say, loving the level of response on this forum. I hope to contribute something back one day!

I've tried both methods, the cull method seems faster computationally, which may be handy to know!

Thanks!

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• Screen Shot 2012-05-02 at 21.08.12.png, 103 KB

Permalink Reply by David Rutten on May 3, 2012 at 4:13am

Note that the first time a component runs it will take a long time to complete because it must be compiled first. Try hitting F5 and then look at the real performance.

--

David Rutten

david@mcneel.com

Poprad, Slovakia

Permalink Reply by Daniel Bates on May 3, 2012 at 4:23am

I refreshed several times, on average the function method was slower.

Not much of a big deal unless you had several several tens of thousands of points though really.