looking to duplicate a a set of branches

this is another simple one, but can't figure it out. I'm trying to take a series of branches and repeat them - but with out their content ending up in the same branches...

so {0:1}, {0;2}, {0:3}...

becomes
{0:1}, {0;2}, {0:3}...
{1:1}, {1;2}, {1:3}...
{2:1}, {2;2}, {2:3}...

and each branch where {A;B} the B is the same irregardless of A...

how? thanks!

Replies to This Discussion

Permalink Reply by Damien Alomar on March 12, 2010 at 7:13pm

I'm not really sure if this can be done parametrically. The easiest way to take care of this is just with two extra path matchers where you just sepecify "A" directly (so the input would be {a;b} and the output would be {1;b}). Then just merge the theree streams together.

Permalink Reply by taz on March 13, 2010 at 12:08pm

I think this will do ya... each branch can have a unique number of items.
(Damien, it's not as bad as I thought it would be...)

Permalink Reply by taz on March 13, 2010 at 1:37pm

Actually, strictly speaking, the first [Path Mapper] isn't necessary....

Permalink Reply by Gabriel on March 13, 2010 at 1:54pm

Damian, Taz...thanks!....

Permalink Reply by Damien Alomar on March 13, 2010 at 9:50pm

Looks good... I thought it would have been worse too, but that does it purdy well, and not too may extra components either (which is a plus)

Permalink Reply by Alpha222 on March 14, 2010 at 10:09am

option 2：

Permalink Reply by Gabriel on March 15, 2010 at 1:19pm

and if I wanted to follow this duplication by converting the hierarchy of branches into a single level where instead of
{0;1},{0:2},{0:3},{1;0},{1;1},...

I would get the following
{0;1},{0:2},{0:3},{0;4},{0;5},...???

Permalink Reply by Gabriel on March 15, 2010 at 1:36pm

ok...I want to combine the power of expressions with the lexer combo mapper - ideally I could use the "max B" in an expression:

{A;B} >> {0;A*(Max(B)+1)+B}

yes, is this possible?

Permalink Reply by Gabriel on March 15, 2010 at 1:37pm

YES! it is...i was just missing a * sign...this is great

Permalink Reply by Gabriel on March 15, 2010 at 1:42pm

er um, no it doesnt - I think instead of getting the Maximum B value for everything in the B column, I'm just getting the B value...

Permalink Reply by taz on March 15, 2010 at 2:18pm

Try {path_index} as the target. {0;path_index} if you need the leading zero.

Check the "Remarks" of the help file for a description.