Simple Tree Structuring Question - Partition List for Branches

Replies to This Discussion

Permalink Reply by David Rutten on May 18, 2017 at 8:53am

So you have:

{0} N = 3

{1} N = 3

{2} N = 5

{3} N = 5

...

Where n=2, x=3 and y=5? And you want:

{0;0} N = 3

{0;1} N = 3

{1;0} N = 5

{1;1} N = 5

...

Or did I misunderstand?

Also, do you know n, x and y, or do you need GH to figure out these values at runtime?

Permalink Reply by Ernst Bay on May 18, 2017 at 10:47am

That is exactly what I am looking for. n is known. x and y are not known but are unimportant. The number of base level branches (or the total number of initial branches) after transformation is not known, but there will be an even number of sub-branches in each branch.

Thank you.

Permalink Reply by Ernst Bay on May 19, 2017 at 1:43pm

Took me a while to figure this out since I had no idea which component to use and because I had no idea how path mapper works (that seems to be the component for the job!). Attached divides branches into groups of 2 (as per the notes above).

Attachments:

• path_mapper.PNG, 19 KB

Permalink Reply by Ernst Bay on May 19, 2017 at 1:45pm

I should have used "floor" to make it more like David's example above. 

Permalink Reply by Congzheng ZOU on August 31, 2018 at 3:55am

That is interesting. Now I have this question. How can you partition your lists in this way:

{0;0} N = 3

{0;1} N = 3

{1;0} N = 5

{1;1} N = 5

{2;0} N = 30

{2;1} N = 30

partition these six branches into three parts:

branch 1:

{0;0} N = 3

{0;1} N = 3

branch 2:

{1;0} N = 5

{1;1} N = 5

branch 3:

{2;0} N = 30

{2;1} N = 30

parthmapper won't change the length of branch, explode tree won't give me two branches in one output