how to set the position of a Curve in C#?

private void RunScript(Curve x, double y, ref object A)
{

    AreaMassProperties.Compute(x).Centroid.X = 2;
    AreaMassProperties.Compute(x).Centroid.Y = 4;
    AreaMassProperties.Compute(x).Centroid.Z = 3;

}

but it doesnot work....the error is: centroid is a return value....

someknow how to set position?

yes ,of course i can use transform,but you need to calculate the vector which minus the origin position...it takes time and not efficient...i just need to set the final centroid position of curve...

Thank you！

Replies to This Discussion

Permalink Reply by djordje on August 18, 2014 at 3:03am

Hi Andrea,
Not all properties could be set. AreaMassProperties properties being one of those.
So, yes, you would have to do it by using Transform.

Permalink Reply by Andrea Lu on August 18, 2014 at 7:12pm

yes,you r right!Djordje,thankyou

Permalink Reply by Arend on August 18, 2014 at 3:33am

You're in luck, because transformations are easy and really fast!

Point3d currentCentroid = AreaMassProperties.Compute(x).Centroid;
Point3d targetCentroid =  new Point3d(2,4,3);

// bit counter intuitive: subtracting two points
// gives a vector in the direction of to - from.
Vector3d transformVector = TargetCentroid - CurrentCentroid;

Transform translation = Transform.Translation(transformVector);
x.Transform(translation);

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