Troubles setting up a parallel Shape in Brep

Replies to This Discussion

Permalink Reply by djordje on December 23, 2013 at 10:39am

Hi Nate,

Try changing your x and y input access types from "Item access" to "List access" (right click on them).

Permalink Reply by Nate Holland on December 23, 2013 at 10:46am

Thanks for the quick response Djordje,

I get a different error when I switch both x and y to list access...

{1;0}
0. Runtime error (ArgumentTypeException): Intersect() takes exactly 2 arguments (1 given)
1. Traceback:
line 25, in run, "C:\Users\nholland\AppData\Roaming\McNeel\Rhinoceros\5.0\Plug-ins\IronPython (814d908a-e25c-493d-97e9-ee3861957f49)\settings\lib\ghpythonlib\parallel.py"
line 8, in script
line 21, in helper, "C:\Users\nholland\AppData\Roaming\McNeel\Rhinoceros\5.0\Plug-ins\IronPython (814d908a-e25c-493d-97e9-ee3861957f49)\settings\lib\ghpythonlib\parallel.py"

I'm not sure what this error is telling me either.

Permalink Reply by djordje on December 23, 2013 at 10:59am

I am not a parallel expert, and have been struggling myself in the last period, but here is my guess:

ghpythonlib.parallel.run() function accepts three arguments:

- name of the function you are calling (in this case: "Intersect")

- list (in this case "x")

- flatten results (in this case "y").

I guess that seems to be the problem: you defined your "Intersect" function with two arguments, and ghpythonlib.parallel.run() is feeding it with only one - "x".

To solve this, just define your "Intersect" function with one argument (let's say "y"), and inside it, use a global variable "x":

import ghpythonlib.components as ghc
import ghpythonlib.parallel

def Intersect(_y):
    result = ghc.ShapeInBrep(x,_y)
    if result: return result

a = ghpythonlib.parallel.run(Intersect, y, True)

Other than that replace your "y" as a third argument in ghpythonlib.parallel.run() with either True or False, as that's what the function is expecting.

And here is the solution Steve Baer made for supplying two arguments into the function instead of one (in a form of a list of tuples, and then unpacking it inside the function.
In your case the code would look like this:

import ghpythonlib.components as ghc
import ghpythonlib.parallel

def Intersect(_breps):
    _x,_y = _breps
    result = ghc.ShapeInBrep(_x,_y)
    if result: return result

breps = []
for item in y:
    breps.append((x,item))
a = ghpythonlib.parallel.run(Intersect, breps, True)

Please, please attach your files for any future issues.

Permalink Reply by Nate Holland on December 23, 2013 at 11:52am

That was exactly it, Thank you.

For others here is the final version that runs with tree access

import ghpythonlib.components as ghcomp
import ghpythonlib.parallel
from System import Object
from Grasshopper import DataTree
from Grasshopper.Kernel.Data import GH_Path

a = DataTree[Object]()
output = [ ]

for i in range(x.BranchCount):
p = GH_Path(i)
brep=x.Branch(i)
shape=y.Branch(i)

def Intersect(Brep2):
result = ghcomp.ShapeInBrep(brep, Brep2)
if result: return result

o = ghpythonlib.parallel.run(Intersect, shape)
a.AddRange(o,p)