simplify Algorithm

Replies to This Discussion

Permalink Reply by Robert Megel on November 1, 2012 at 11:07am

This is how it looks like right now

Permalink Reply by djordje on November 1, 2012 at 12:03pm

Hi Robert,

I might not understand the concept, but if you just want to get all intersected curves inside of brep, and all the rest ones, outside of it, then you do not need to pick each one of them separately in order to trim it from the brep. Like this:

Is that what you need?

Attachments:

• trim.gh, 4 KB

Permalink Reply by Robert Megel on November 1, 2012 at 12:46pm

i am sorry for my bad explanation ;-)

basically i want to know how much intersections/intersectionpoints have every line from the first point, second point, thirt point...

in words:   

point "0" is connected to 10 points --> 3 of 10 Lines have an intersection with the brep

point "1" is connected to 10 points --> 5 of 10 Lines have an intersection with the brep

point "2" is connected to 10 points --> 2 of 10 Lines have an intersection with the brep

I actually got this information but as you can see the algorithm become pretty long

Permalink Reply by djordje on November 1, 2012 at 4:48pm

I think this might be it:

Point, node, it's the same.

Attachments:

• trim2.gh, 9 KB
• trim2.3dm, 63 KB

Permalink Reply by Robert Megel on November 3, 2012 at 5:01am

oooh thank you very much, that was extremly helpfull. Thanks! =)

Just one more question. What is the use of the Path Mapper there? Couldn't you connect the simplified "Data"-Component directly to the list lentgh? ;-)

Permalink Reply by Robert Megel on November 3, 2012 at 5:27am

Oh i tried it with multiple Breps and that doesn't work. Do you have an idea how to fix that?

greetings

Robert

Permalink Reply by Robert Megel on November 3, 2012 at 6:46am

Ah i have solved the problem by flatten the points of the other curve. Thank you again!

Permalink Reply by djordje on November 3, 2012 at 8:27am

I did not see your reply on time.
Glad it worked.

Permalink Reply by Toussaint Jimenez Rojas on November 1, 2012 at 11:20am

do you know how to use Cross reference component ? 

maybe can be a way

i cant prove it now cuz i dont have R3D + GH here at the office  but maybe you have to take a look what crossreference do