Series in C#

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Permalink Reply by Giulio Piacentino on January 4, 2011 at 3:26am

Hi Mirco,

this should do:

 

//List of integer values, with a default capacity of (C) elements
List<int> result = new List<int>(C);

for (int i = 0; i < C; i++)
   result.Add(i * N + S); //add to the result list

O = result;

i is less than C is the loop invariant.
S shifts all results, setting a start when i equals 0, soi * N equals 0, too.

This page contains the full specification.
- Giulio
____________________
giulio@mcneel.com
McNeel Europe, Barcelona

Attachments:

• Series2.ghx, 52 KB

Permalink Reply by Mirco Bianchini on January 4, 2011 at 3:29am

Super Giulio!!

Thank you