Relative Items for two data trees

It seems like this this is not working correctly.

I was shifting a list {1}

The B Output seems correct but A output appears to output {-1}. Reading the help, I understood the A to just be the original list.

Stan

Replies to This Discussion

Permalink Reply by David Rutten on June 27, 2011 at 3:49am

Hi Stan,

the way to read a relative offset path is to append the items in the offset path to the original path. So if the offset path is:

{0;0;1}(1)

and you apply it to an existing path, say:

{0;2;0}(4)

you'll get:

{0+0; 2+0; 0+1}(4+1) which equals {0;2;1}(5)

There's no "A" or "B" placeholders in there like you'd get with the PathMapper. In fact, I always specifically prepend the sign of the offset, just to make it more obvious what's happening:

{0;0;+1}(+1)

If the new path doesn't exist within the data structure, then the wrapping logic comes into play as well.

David Rutten

david@mcneel.com

Poprad, Slovakia

Permalink Reply by Stan Carroll on June 27, 2011 at 12:43pm

Should have sent this earlier...

Attachments:

relative two data trees.ghx, 68 KB
relative two data trees.png, 218 KB

Permalink Reply by David Rutten on June 28, 2011 at 4:06am

The whole point of the Relative Item components is to create data pairs. Therefore the data structure layout of both A and B outputs should be identical, otherwise there would be 'radicals'. The only difference between A and B, is which particular data item is stored at a specific location* inside the data tree.

David Rutten

david@mcneel.com

Poprad, Slovakia

* a data location is defined both by the path (the curly bracket thing) and the index (the round bracket number).

Permalink Reply by Stan Carroll on June 28, 2011 at 8:20am

Ah, Now I understand. Thanks for working this through with me.

Stan

Permalink Reply by Stan Carroll on June 27, 2011 at 9:45am

I am certain I have not done a good job of explaining myself so... I can possibly address my findings by asking one question which should either confirm my suspicion of a bug or not.... What list can one expect get from the A output?

Sorry to be so unclear.

Stan

Permalink Reply by David Rutten on June 27, 2011 at 9:50am

Ah, the data inside A is exactly the same as the data inside T.

Except when no matching relative item can be found (because wrapping has been disabled) in which case A will not contain that particular data items from T.

David Rutten

david@mcneel.com

Poprad, Slovakia

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