recursive cube

Replies to This Discussion

Permalink Reply by Laurent DELRIEU on May 6, 2017 at 12:25pm

Hello,
Did you search on this website?
Did you look at that ?
http://www.grasshopper3d.com/forum/topics/recursion-of-mesh

Permalink Reply by maiabdelsalam on May 6, 2017 at 2:27pm

Hello Laurent,

Actually, It is a good link to check. Thanks alot

Permalink Reply by peter fotiadis on May 7, 2017 at 1:57am

Get the orthodox way to make a conditional recursion ... but using (obviously) code

PS: No meshes around because I hate meshes.

Attachments:

• Fractal_AdjacentBoxes_V1.gh, 119 KB

Permalink Reply by maiabdelsalam on May 7, 2017 at 5:06am

Thanks Peter. That was so near to what i was thinking of. I will try to modify it with the constraints I have . but sorrowfully I am not good at C#. I tried Vb and python before. regarding mesh, I was about to convert the box into mesh as a trial. Thank u again 

Permalink Reply by peter fotiadis on May 7, 2017 at 6:51am

Added 5 "modes" to play with (4 are random).

Attachments:

• Fractal_AdjacentBoxes_V1A.gh, 118 KB

Permalink Reply by maiabdelsalam on May 7, 2017 at 10:15am

Thank you peter for your help and patience. Here i added some constraints to explain what i mean 

there are constraints such as the generated cubes should be always at the middle and parametric with the variation of the original cube dimensions. but i can do the script on the base of the box in 2 dimensional only .. i want these squares extruded with the same height of the square side.

forgive my ignorance in scripting, I am an early beginner

Attachments:

• gh.gh, 15 KB

Permalink Reply by peter fotiadis on May 7, 2017 at 10:38am

FYI: If D2 = 1-D1 then the next generation mini Box (the child Box) is centered at the corresponding side/face center (of the parent Box).

D3 controls the "extrude" part as follows: measures the appropriate vector (per side - that's NOT unitized, mind: thus the shrink is "progressive") using the parent Box 8 points and multiplies it by D3. All that if the random option is 1 (i.e. "No") - else random things happen depending on the option on duty.

Of course for a "finer" control 2 D1 (min max) and 2 D2 (ditto) values are required.

BTW: You can translate C# to/from VB (Google that) ... but Python is another animal

Permalink Reply by peter fotiadis on May 7, 2017 at 10:57am

Here's a more "suitable" D1/D2 combo for the center placement part:

Permalink Reply by peter fotiadis on May 7, 2017 at 11:36am

And the Python  thingy of yours ... well ... are you sure that THIS is what you want as an output? (I don't think so).

Anyway I've added some stuff in order to visualize properly the P output (a bit faulty/freaky if you ask me).

Attachments:

• user_gh.gh, 18 KB

Permalink Reply by mark zirinsky on May 7, 2017 at 2:05pm

ah, this i so close to a project I have in mind, but haven't gotten to, doing same but with 6 sided, hexagonal geometry, to model .. a snowflake 

Permalink Reply by peter fotiadis on May 8, 2017 at 12:14am

In general the "tricky" part is to assign a value on each child indicating the location (see the fullHistoryTree on my example).

For a cube and for that arrangement desired options are E(ast), S(outh), W(est), N(orth) (2 more are required if we want top-bottom children).

Since each child Box has his faces oriented the same way the location rule applies to all.

The only other thing is to realize that for an item positioned, say, South it can have children in any orientation except the straight opposite (North) ... etc etc.

Therefor for a 3d/2d hexagon you'll need  6 orientations (S, SE, NE, N, NW, SW) ... but clash checks are more paramount than in the rectangle/cube case. 

Permalink Reply by peter fotiadis on May 8, 2017 at 2:00am

Added some ultra LOL stuff ... but I can't attach anything since the known (a bit nerve braking) Forum issue ... blah, blah.

• ‹ Previous
• 1
• 2
• Next ›
• Page