PLANE NORMAL OF A CURVE

HOW CAN I CREATE A PERPENDICULAR PLANE ON A 2D CURVE (NOT A STRAIGHT LINE) FOR A GIVEN POINT?

PLS NOTE THAT MY CURVE IS COMPOSED OF NUMEROUS POINTS. IN ORDER TO BE PRECISE, IT HAS A DEGREE HIGHER THAN 2.

THNX

Replies to This Discussion

Permalink Reply by Chris Ingram on May 5, 2012 at 3:50am

Use the 'perp frame' component and the points as parameters for the frame locations (t input).

Permalink Reply by Firat Aydin on May 5, 2012 at 6:21am

thanks for your help chriss but i have a different issue here.

well first of all my curve is a dome like curve.

it is composed of a couple of thousands of points.

it is such a function, Z=An*x^a+ blah blah blah.. and 2<a<11

the x and z values do not have regular intervals. (the curve is not regularly segmented)

therefore i must find the plane for an instantaneous x,z value.

can you help me for that one?

thnx

Permalink Reply by Chris Ingram on May 5, 2012 at 7:53am

Not sure I understand exactly what you are asking - did you try using the 'curve cp' component to find the location t parameter for the perp frames with irregular intervals

Permalink Reply by Firat Aydin on May 5, 2012 at 9:59am

if I understood your way well;

your gh definition divides the curve equal segments. and creates a point at the junction of each segment. then at those points are the origin of the normal planes, right?

however i want a normal plane of the curve for an arbitrary coordinate. for example where x=5,y=0,z=15 (i assume this point is on my Gz=x curve) is satisfied, I want to create a normal plane with respect to curve. and this point is not PARTICULARLY MATCHING YOUR SEGMENT POINT.

If Im wrong with my first claim about your gh definition plz correct me.

Thnx again

Permalink Reply by Chris Ingram on May 5, 2012 at 10:11am

as i said before use the CURVE CP COMPONENT to do the same thing for arbitrarily located points on a curve

Permalink Reply by RAF on March 17, 2017 at 6:28am