Lofting

Replies to This Discussion

Permalink Reply by y.KWON on October 21, 2012 at 9:22am

Do you have reason, that you will loft the curves with Python?

GH Default Loft Component can already create Loft Surface from Polylines.

Permalink Reply by naciem nowrouzi on October 21, 2012 at 9:33am

I am just learning python and thought using grasshopper python component would be easier for me to learn since it is more visual and I can see step b step if my code is working...Also Python is a course that I am taking.

n- 

Permalink Reply by y.KWON on October 21, 2012 at 9:42am

I think...

1. you need to feed your curves in one list. not each other.

2. assign your access type as list in python component.

3. feed your curves to python component.

See Rhino IronPython Document.

Syntax

rhinoscriptsyntax.AddLoftSrf ( object_ids, start=None, end=None, loft_type=0, simplify_method=0, value=0, closed=False )

rhinoscript.surface.AddLoftSrf ( object_ids, start=None, end=None, loft_type=0, simplify_method=0, value=0, closed=False )

Permalink Reply by Mostapha Sadeghipour Roudsari on October 21, 2012 at 9:51am

Hi Naciem,

Yong Sung is correct but you can make the current script work as well. Like: rs.AddLoftSrf((HEX1, HEX2))[0]

As a side note. You don't need to change the Type Hint. You can just leave it as ghDoc object.

Permalink Reply by naciem nowrouzi on October 21, 2012 at 9:57am

Hi Mostapha,

Thank you for your response. Can you please explain to me why you would write it as ((HEX1, HEX2))[0]. 

I knew that it has to be a list and I was using ([HEX1], [HEX2]).

Thanks,

Naciem

Permalink Reply by Mostapha Sadeghipour Roudsari on October 21, 2012 at 10:08am

Hi Naciem,

[HEX1], [HEX2] are two different lists that each one has one member. What you need is a list with two members (both curves). That is why I wrote it as [HEX1, Hex2]. In this way  AddLoftSrf takes the list as object_ids.

In case of ([HEX1],[HEX2]) AddLoftSrf takes [HEX1] as the first input which is object_ids and [HEX2] as the second input which is start. That's why you get no surface.

Mostapha

Mostapha

Permalink Reply by naciem nowrouzi on October 21, 2012 at 10:20am

Mostapha,

The first time you wrote ((HEX1, HEX2))[0]. I also just tested [HEX1, Hex2] which works fine. How does python read and accept ((HEX1, HEX2))[0] as well when HEX1 and HEX2 are not a list, but 0 is? How did you know we need to add [0] to make it work?

I'm sorry with all these primitive questions.

Thanks,

Naciem

Permalink Reply by y.KWON on October 21, 2012 at 11:14am

rs.AddLoftSrf will return a List of created Surfaces.

It means...

srfList =  rs.AddLoftSrf((HEX1, HEX2))

and the meaning of  rs.AddLoftSrf((HEX1, HEX2))[0]

is the first item in srfList. it is equal to srfList[0]

Permalink Reply by Mostapha Sadeghipour Roudsari on October 21, 2012 at 11:31am

1. (a,b) makes a tuple whereas [a,b] makes a list in Python:

"Though tuples may seem similar to lists, they are often used in different situations and for different purposes. Tuples are immutable, and usually contain an heterogeneous sequence of elements that are accessed via unpacking (see later in this section) or indexing (or even by attribute in the case of namedtuples). Lists are mutable, and their elements are usually homogeneous and are accessed by iterating over the list."

In this case it doesn't really matter and both (HEX1, HEX2), [HEX1, HEX2] work the same for you.

 

2. As Yong Sung posted rs.AddLoft returns a list of surfaces, so I used [0] to get the first item of the list.

Permalink Reply by naciem nowrouzi on October 21, 2012 at 11:37am

Mostapha and Yong Sung,

Thank you so much for all you explanations. You've been very helpful!

Permalink Reply by Mostapha Sadeghipour Roudsari on October 21, 2012 at 9:56am

Make the same change in your script and it will work. Line 64.