Intersection of Box and Circle/Arc/Surface

Replies to This Discussion

Permalink Reply by Dedackelzucht on November 24, 2011 at 3:27am

like this?

Best Regards

DeDackel

Attachments:

• DeDackel.gh, 4 KB

Permalink Reply by Lukas Mosser on November 24, 2011 at 3:39am

Sort of. But the circle is slanted inside the box. 

Also, what you created is only the lines not as a new joined up surface. 

Like this .....

The Black boundary should be the outer boundary of the new surface so the 3 straight lines and the curve at the bottom are the edges of a new surface.

Thank you for your help 

Permalink Reply by Dedackelzucht on November 24, 2011 at 4:05am

ok, like this?

Attachments:

• DeDackel_2.gh, 7 KB

Permalink Reply by Lukas Mosser on November 24, 2011 at 9:38am

I'm sorry but this still doesnt work. In 90 % of the times the list at the end returns the outside surface. And makes your method unstable. 

Isnt there a function like a CreateSurfaceFromBodyAndCurve(Surface, Body){ return Surface Inside Body and on Surface)

 

Subtract From Surface Everything outside a box.

 

Thank you.

 

Permalink Reply by Dedackelzucht on November 25, 2011 at 2:06am

here are two more possibilities.

try to think in a working process, even a component isn´t a one step function.

And I think this is what its all about thinkin of how to get from Input A to Output B. That is actually waht makes so much fun about working with gh

 

Best Regards

DeDackel

Attachments:

• DeDackel_3.gh, 21 KB