How to use the interpolator class in VB?

Hello,
I am trying to implement in VB the Interpolate data (interp) component, but does not work me like it should.

I've done this:

Private Sub RunScript(ByVal D As List(Of Double), ByVal t As List(Of Double), ByRef A As Object)

Dim interp As interpolator = New Interpolator(D.ToArray)

Dim list As New list(Of Double)

For i As int32 = 0 To t.count - 1
Dim paso As Double = (1 / t.count) * i
Dim val As Double = interp.InterpolateLinear(paso)
list.add(val)
Next

A = list

End Sub

Or I am missing something, or I'm doing it wrong, or I misunderstood what this method does.

Could someone help me understand what's going on?

Thank You!!!!

Replies to This Discussion

Permalink Reply by Daniel González Abalde on March 23, 2015 at 2:48pm

Could someone help?

Permalink Reply by Pieter Segeren on March 23, 2015 at 3:43pm

I tried, but to no avail... what I did notice, is that the native Interpolate component has the t input access set as Item - not List... I'm sorry I can't be of more help.

Permalink Reply by Javier Vizoso on March 23, 2015 at 4:24pm

I tried as well and found that Linear only works on 2 values, while CatmullRom/Cubic work with the first 3. Meanwhile, i wrote a quick interpolator in python (shouldn't be too hard to translate). Here's a website with some easing equations you can plug in: http://gizma.com/easing/ .

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