algorithmic modeling for Rhino
Hey guys,
I'm am trying to randomize three different objects (square, circle, and cylinder) on a point grid. I am having trouble assigning different values to the geometry so from the base reference point it can either run the square, circle, or cylinder.
I think using some sort of boolean list command might be most successful? I have separated my randomly generated list of values but perhaps somehow need to assign value, or set a condition in order to reference the different geometries? Help would be greatly appreciated!
Thank you
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I'm not sure if this is what you want, or if it's the best way...
Awesome that's exactly what I had in mind, if you don't mind could you explain why you multiplied the random values and the geometry list and also what the difference of plugging in the nearest, floor, or ceiling list does to the list generated? They seem to generate different list values, are they just three different random options?
Thank you for the response!
I'm a newbie :)
Multiplying the 0..1 random values by the length of the "Geo" list (3) is intended to generate random values of 0, 1 or 2, corresponding to the Sphere, Box and Cone.
The three outputs of the 'Round' component - 'N (Nearest)', 'F (Floor)' and 'C (Ceiling)' - are standard math terms for obtaining an integer from a floating point value: Floor and ceiling functions
Actually, I probably did that wrong... It should be (length-1) and 'N (Nearest)'.
By the way, you don't need to use Rhino geometry for your grid of points; they can be generated in GH, or you could use the "Internalize data" feature of your first 'Point' component to save the data in the GH file and disconnect it from Rhino.
Hello Will.
In order to get random integers corresponding to your geometry, you can :
- generate random numbers betweem 0 and 1, multiply them by the number of optional geometries (in your case 3) to get numbers between 0 and 3, round these values to get an integer (if you have 1.8665865548 Floor value will be 1, Ceiling value will be 2, and Nearest will be 2) and use the result for the List Item component. That is what Joseph did here.
- or you can also use the range input of the random component with the geometry list lenght and the integer option of the random component (with right click) like shown below.
In both case, you get the same result !
Good luck !
Yeah, as I was drifting off to sleep last night, I realized I could probably have configured the 'Random' component to generate integers in a range but didn't think it was important enough to get out of bed. :) Then when I looked this morning, I didn't notice the "Integer Numbers" option on the 'Random' component - thanks for mentioning it. Revised code attached.
P.S. Your code is generating values from 0..3 instead of 0..2 - there are only three geometries to choose from: Sphere, Box and Cone. As I noted earlier, it should be (length-1) to get 0..2 as the index value for 'List Item'.
Hey Joseph and FRiou,
Thank you for the assistance learning lots and super fun. I played a bit more, adding random sizing and double stacking to the objects. I have a problem stacking the objects so there isn't a gap between them. Before randomizing the geometry size it was fine for me to multiply the referenced radius multiply it by 2 and move the geometries. Now that sizes are randomize this approach doesn't seem to work. Also is there a way to reorganize the geometries into their separate shapes so I can bake them and organize them as squares, cylinders, and circles?
Help would be greatly appreciated!
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