how to organize a list of data

Replies to This Discussion

Permalink Reply by David Valent on June 23, 2016 at 3:10am

Can't see your geometry.

You need to internalise your original references

Permalink Reply by Armin Seltz on June 23, 2016 at 6:03am

You just take the data and use "shift list" and shift it by -1. You also take you data and delete the last entry in each list using "cull index" and using index -1. Now you connect both lists to a line component.

Hope that helps! 

Permalink Reply by Armin Seltz on June 23, 2016 at 6:14am

Actually, sorry, that wasn't quite right. You also need to cull the last index of the shifted list, because usually you dont want to connect the last point again to the first point.

Here is an example:

Attachments:

• lines_between_points.gh, 10 KB

Permalink Reply by Oliver Dark on June 23, 2016 at 8:06am

thank you. it helped me a lot!

Permalink Reply by David Stasiuk on June 23, 2016 at 8:59am

A good trick here is to just use two shift paths, one set to "Shift" 1 and the other to -1, and then set "Wrap" to false. Not wrapping the lists pushes the shifted values out of the list and reduces the list size...

Permalink Reply by Armin Seltz on June 23, 2016 at 9:38am

Nice! Will remember that.

Thanks.

Permalink Reply by Matt Gaydon on June 23, 2016 at 10:46am

You can do this will Relative Item quite easily 

You need to panel tree with the data tree (it works fine here with {0} and simplify)

but if you get an error when you plug it in a larger code this will be usually why.

This Video should explain how it works for more than just this Shift List question.

https://vimeopro.com/rhino/grasshopper-masterclass-with-david-rutte...

Hope it some help.

Matt

Permalink Reply by Oliver Dark on June 26, 2016 at 6:55am

Thanks a lot!

Oliver