Grasshopper

algorithmic modeling for Rhino

Getting Branch Indexes as Ints

Hi all,

I have a python script which is iterating through a data tree. The incoming branches look something like this:

{0;0}

{1;0}

{1;1}

{1;2}

{2;0}

{2:1}

{3;0}

I'm iterating through using:

for i in range(inputTree.BranchCount):
    inputThisBranch = inputTree.Branch(i)

...which graps each branch in sequence. I was wondering if it was possible to then:

a) get the first index numbers of each branch an integer, ie. '0' for the first branch, '1' for the next three, '2' for the next two...

b) get the 'depth' of the path for all branches, ie. '2' for each

Is there a way to do this? I haven't been able to find the answer by searching...

Thanks,

Ben

Views: 2089

Replies to This Discussion

Permalink Reply by David Rutten on August 1, 2014 at 3:11am

Yes, to get this information you have to also iterate over the Paths of the tree

for i in range(inputTree.BranchCount):

  inputThisBranch = inputTree.Branch(i)

  pathLength = inputTree.Path(i).Length

  pathFirstNumber = inputTree.Path(i)(0)

--

David Rutten

david@mcneel.com

Permalink Reply by Ben Minton on August 1, 2014 at 3:32am

Brilliant! Thanks

Permalink Reply by djordje on August 1, 2014 at 3:44am

Just a small addition to David's reply:
Use square brackets when accessing element from python sequences:

pathFirstNumber = inputTree.Path(i)[0]

Permalink Reply by Giulio Piacentino on May 31, 2021 at 2:54am

If you use list_to_tree, you can transform this forest into a list of list as well. See this example:

https://gist.github.com/piac/ef91ac83cb5ee92a1294#gistcomment-3763417

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