algorithmic modeling for Rhino
Getting Branch Indexes as Ints
Hi all,
I have a python script which is iterating through a data tree. The incoming branches look something like this:
{0;0}
{1;0}
{1;1}
{1;2}
{2;0}
{2:1}
{3;0}
I'm iterating through using:
for i in range(inputTree.BranchCount):
inputThisBranch = inputTree.Branch(i)
...which graps each branch in sequence. I was wondering if it was possible to then:
a) get the first index numbers of each branch an integer, ie. '0' for the first branch, '1' for the next three, '2' for the next two...
b) get the 'depth' of the path for all branches, ie. '2' for each
Is there a way to do this? I haven't been able to find the answer by searching...
Thanks,
Ben
Views: 2103
Replies to This Discussion
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Permalink Reply by David Rutten on
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Yes, to get this information you have to also iterate over the Paths of the tree
for i in range(inputTree.BranchCount):
inputThisBranch = inputTree.Branch(i)
pathLength = inputTree.Path(i).Length
pathFirstNumber = inputTree.Path(i)(0)
--
David Rutten
david@mcneel.com
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Permalink Reply by Ben Minton on
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Brilliant! Thanks
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Permalink Reply by djordje on
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Just a small addition to David's reply:
Use square brackets when accessing element from python sequences:pathFirstNumber = inputTree.Path(i)[0]
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If you use list_to_tree, you can transform this forest into a list of list as well. See this example:
https://gist.github.com/piac/ef91ac83cb5ee92a1294#gistcomment-3763417
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