Grasshopper

algorithmic modeling for Rhino

Hey, i have a question how i could get something out of a private void. The Question is in the c# code:

private void RunScript(object curve, ref object resFct)
{


//the following line needs to be exactly this. no changes are allowed,

//because this function goes to another node wich then works with this...

Func < OpenTK.Vector2d, OpenTK.Vector2d, OpenTK.Vector2d > resultingFunction = TopologyReaction;

resFct = resultingFunction;

}

// <Custom additional code>
public static OpenTK.Vector2d TopologyReaction(OpenTK.Vector2d parentPt, OpenTK.Vector2d newPt)
{

//and here i need to work with the curve (object curve) from private void

//how do i do this?!? Whats the trick here?


parentPt = newPt;
return parentPt;
}

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Replies to This Discussion

Your TopologyReaction method needs to get a reference to the curve. Since you're not allowed to change the signature of it, you'll need to embed the function into a class instance which has this reference. Ie. instead of a public static method, what you do is create a new type:

public sealed class TopologyReactionWrapper

{

  private readonly Curve _curve;

  public TopologyReactionWrapper(Curve curve)

  {

    _curve = curve;

  }

  public OpenTK.Vector2d TopologyReaction(OpenTK.Vector2d parentPt, OpenTK.Vector2d newPt)

  {

    // You have access to parentPt and newPt here, as well as _curve.

  }

}

Then you return a delegate to the instance method from within RunScript:

private void RunScript(Rhino.Geometry.Curve curve, ref object resFct)
{

  TopologyReactionWrapper wrapper = new TopologyReactionWrapper(curve);

  Func<OpenTK.Vector2d, OpenTK.Vector2d, OpenTK.Vector2d> func = wrapper.TopologyReaction;

  resFct = resultingFunction;

}

I think.... I haven't tried this code, but if it doesn't work it should at least be close.

Hey, thank you so much!! it is hard for me to understand whats happening, so i dont really know how to fix the error in this line:

    resFct = resultingFunction;

it sais: 

"1. Error (CS0103): Der Name 'resultingFunction' ist im aktuellen Kontext nicht vorhanden. (line 90)" 

translated it is something like: name "resultingFunction" is not available in the actual context...

Is there an easy fix for it?

Thank you so much - especially getting help from the master himself here! ;)

Cheers

NEVER MIND... Stuped me... 

"    resFct = func;"

Thank you so much, ill see how far i get till i ask the next question ;)

sorry, I renamed it func but forgot to rename it everywhere.

in fact... too advanced ;)

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