duplicate the component "Shortest List" into a custom component

Replies to This Discussion

Permalink Reply by David Rutten on July 6, 2017 at 9:32am

It depends on whether you want to create new lists that match, or whether you're happy just creating a single loop that acts like Shortest List.

For looping:

int shortest = int.MaxValue;

shortest = Math.Min(shortest, List1.Count);

shortest = Math.Min(shortest, List2.Count);

shortest = Math.Min(shortest, List3.Count);

// ... etc. etc. with all your lists.

for (int i = 0; i < shortest; i++)

{

  var value1 = List1[i];

  var value2 = List2[i];

  var value3 = List[3];

  // ... etc.

}

Actually creating modified lists will also involve first finding the shortest one, and then using something like RemoveRange() to cut all lists down to size.

Permalink Reply by Mathis on July 6, 2017 at 10:29am

I am interested in this "Remove Range" fonction. 

I tried to do it but I think that I made something wrong. 

To use this fonction it's something like : List.RemoveRange("start_index", "number of object to remove");

isn't it ? 

 

Permalink Reply by Michael Pryor on July 6, 2017 at 10:29am

Like David said but I just made new lists rather than cutting the lists with RemoveRange()

private void RunScript(List<double> x, List<double> y, List<double> z, ref object A, ref object B, ref object C)
{
List<double> xShort = new List<double>();
List<double> yShort = new List<double>();
List<double> zShort = new List<double>();

int shortestList = Math.Min(x.Count, Math.Min(y.Count, z.Count));

for (int i = 0; i < shortestList; i++)
{
xShort.Add(x[i]);
yShort.Add(y[i]);
zShort.Add(z[i]);
}

A = xShort;
B = yShort;
C = zShort;

}

Attachments:

• ShortestList.gh, 7 KB

Permalink Reply by Mathis on July 7, 2017 at 3:56am

ok thank you very much !