Deleting points by x- and y-value

Hello,

I have a python script that will output a list of points (x-, y- and z-coordinates) (see image). Now I want to delete the points that lie between certain x- and y-values. For instance if a point lies between a x-value of 2750-3000 AND a y-value 1500-1750 the point has to be deleted, in this example point nr. 13 has to be removed from the list.

Thanks in advance

Attachments:

Deleting points by x and y value.jpg, 201 KB

Replies to This Discussion

Permalink Reply by Ortler Mark on March 22, 2017 at 3:21am

Have a look at this.

class MyPoint:

X = 0
Y = 0

def __init__(self, x , y):
self.X = x
self.Y = y

def __repr__(self):
return "({0}, {1})".format(self.X, self.Y)

Points= [MyPoint(0,1),MyPoint(2751,1600),MyPoint(3001,1600), MyPoint(3000,1500), MyPoint(2999,1749)]

XRange = (2750,3000)
YRange = (1500,1750)

filtered = [p for p in Points if XRange[0] < p.X < XRange[1] and YRange[0] < p.Y < YRange[1]]

print(filtered)

Permalink Reply by Roman on March 22, 2017 at 4:33am

I managed to solved it by meself via another method. However this is an even more efficient method, thanks.

Permalink Reply by Ortler Mark on March 25, 2017 at 2:04pm

Just to show up a python-syntax which is great ;)

Permalink Reply by Anders Holden Deleuran on March 22, 2017 at 4:45am

Unless I'm misunderstanding the problem, this is pretty straightforward using a conditional statements within a loop:

Attachments:

170322_CullPoints_YX_Coords.gh, 6 KB

Permalink Reply by Roman on March 22, 2017 at 5:49am

No you didn't misunderstood the problem, this was exactly what I was looking for. Short and effective piece of script, thank you.

Permalink Reply by Sid on March 25, 2017 at 1:20pm

Awesome Anders. How can we select the selective points what we want. may be by index numbers or any other method. Would appreciate if you could help on this.

Thanks in advance

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