Grasshopper

algorithmic modeling for Rhino

Hi all, 


How would you arrange this data tree :

{0;1}, {0;2}, {0;3}, {0;4}, {1;1}, {1;2}, {1;3}, {1;4}, {2;1}, {2;2}, {2;3}, {2;4}

into something like:

[{0;1}, {0;2}, {0;3}, {0;4}], [{1;1}, {1;2}, {1;3}, {1;4}], [{2;1}, {2;2}, {2;3}, {2;4}]


So then I can do operations separately within each group...

Views: 1746

Replies to This Discussion

Hi Roger,
The square brackets represent a single list?

If that is so, then use "Shift paths" component.

If you use "shift paths" with the default input of -1 it will remove the last index, leaving you with a tree that is {0}, {1}, {2}. Then, after you perform your operations at that level (so long as your elements then remain in the same order as when you shifted paths) you can re-apply the original data structure using the "unflatten tree" component:

Use the [Split Tree] component with some masks, such as: {0;?} to get all of the first branch etc.

Also read http://www.grasshopper3d.com/forum/topics/datatree-selection-rules?...

Try:

{A;B}(i) --> {A;i}

also, if you have Tree Sloth you can use the "flip last matrix" component, which swaps index for the last non-uniform path index. You'll have to join "Milk Box" to get it...http://www.grasshopper3d.com/group/milkbox/forum/topics/tree-sloth

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