algorithmic modeling for Rhino
Hi everyone!
i wanted to ask if there is a way to create polygon according to a given area? for example, lets suppose i need a covered area of 36 sq ft and whatever shape it takes to cover that area is irrelevant to me. i understand one might require to give a range of length and width for this but that would again limit me to a certain shape i.e. rectangle.
so, is there a simple way to do this?
regards!
Tags:
Moved from FAQ into Discussion.
--
David Rutten
david@mcneel.com
Tirol, Austria
Hi Umar,
If you can come up with a random polygon generation then scaling it to be the correct area is easy.
S = (A1 / A0)^0.5
Where S is the scaling factor
A0 is the Polygon Area
A1 is the Intended Area
^0.5 is all raised to the power of 1/2 (which is another way of saying square root)
thanks danny!
sorry david, thought such a general query belonged to FAQs.
Welcome to
Grasshopper
Added by Parametric House 0 Comments 0 Likes
Added by Parametric House 0 Comments 0 Likes
Added by Parametric House 0 Comments 0 Likes
Added by Parametric House 0 Comments 0 Likes
Added by Parametric House 0 Comments 0 Likes
© 2024 Created by Scott Davidson. Powered by