convert Array of Array into a Data Tree

Is there an easy way to cast an Array or Array (or list of list) into a Data Tree?

I tried using a tree.AddRange() since it was supposed to be able to receive IEnumerable[]() but it throws an exception that such cast is not valid.

I am operating on lists and my final product might be a multi level nested list such as:

_list = [[x],[x],[[x],[x],[x]]]

Here's my code:

# recursive function to process any input list and output
# matching structure list
def process_list(_func, _list):
return map( lambda x: process_list(_func, x) if type(x)==list else _func(x), _list )

def toRHObject(item):
if type(item) == ms.MSEllipse:
return item.toRHEllipse()

#EllipseOut = DataTree[rc.Geometry.Point3d]()
if _import:
_tree = DataTree[rc.Geometry.Ellipse]()
some_data = process_list(toRHObject, data)
someList = Array[Array[rc.Geometry.Ellipse]](map(tuple, some_data))
outEllipses = _tree.AddRange(someList)

Here's my some_data when I try to cast it:

Array[Array[Ellipse]]((Array[Ellipse]((<Rhino.Geometry.Ellipse object at 0x0000000000000064 [Rhino.Geometry.Ellipse]>)), Array[Ellipse]((<Rhino.Geometry.Ellipse object at 0x0000000000000065 [Rhino.Geometry.Ellipse]>))))

Replies to This Discussion

Permalink Reply by Mostapha Sadeghipour Roudsari on December 3, 2014 at 6:31pm

Hi Konrad,

If you know the depth of your list will be 2, then here is an example:

Attachments:

addRange.gh, 6 KB

Permalink Reply by konrad k sobon on December 3, 2014 at 6:35pm

that's the main issue here. My process_list() function operates on/outputs any depth of list. I was hoping for something more flexible: any depth list to datatree. Suggestions?

Permalink Reply by Giulio Piacentino on December 4, 2014 at 7:26am

Hi Konrad,

because this functionality is requested quite often, I wrote this sample that I think does what you are asking.

As a side comment, for large lists it would still be more efficient to create the tree directly rather than with this converting function; but this function is arguably more convenient for the programmer.

Thanks, I hope this helps,

Giulio
--
Giulio Piacentino
for Robert McNeel & Associates
giulio@mcneel.com

Attachments: