CCX index problem in GH version 0.6.0043

Replies to This Discussion

Permalink Reply by Manuel on December 13, 2009 at 11:29am

For every curve it will create a new path (see the path numbers). I think that if you select "longest list" the CCX component only search for the first intersection on every curve, so you have only one point on every path.

If you have groups of curves on different branchs, you can use the path mapper to group your intersection points, try with {A;B;C} -> {A;B}

Permalink Reply by David Rutten on December 13, 2009 at 11:47am

The logic is as follows:

Since CCX can generate multiple answers for a single curve, the output is always stored in lists, even if each list only has a single item. Every component which (potentially) output multiple items of data for a single input item has this behaviour.

--
David Rutten
david@mcneel.com
Poprad, Slovakia

Permalink Reply by Bas Goris on December 13, 2009 at 12:22pm

Thanks for this answer.
My example has every time only one solution. How can I make a list of it again? (My list has 360 items)
Cheers, Bas

Permalink Reply by Manuel on December 13, 2009 at 1:15pm

if you want only one list, use the flatten tree component.

Permalink Reply by Bas Goris on December 13, 2009 at 1:31pm

I want a list with index numbers from 1 till 360

Permalink Reply by Pep Tornabell on December 13, 2009 at 3:26pm

What Manuel said is right. Faltten and flatten... all objects in one single list, with indexes from 0 to the last item u have.

The parameter viewer is a good component to follow path, trees and even forests

Permalink Reply by David Rutten on December 14, 2009 at 3:19am

You may not want to flatten the entire structure all the time. Sometimes you merely with to flatten only the items in the last path number:

{0;0;0;0} (N = 2)
{0;0;0;1} (N = 2)
{0;0;0;2} (N = 2)
{0;0;0;3} (N = 2)
{0;0;0;4} (N = 2)
{0;0;1;0} (N = 2)
{0;0;1;1} (N = 2)
{0;0;1;2} (N = 2)
{0;0;1;3} (N = 2)
{0;0;1;4} (N = 2)

Flattening this structure using the Flatten component would result in:

{0} (N = 20)

However, using a Path Mapper with the following masks will flatten is somewhat more intelligently:

{A;B;C;D} -> {A;B;C}

Now, you get:

{0;0;0} (N = 10)
{0;0;1} (N = 10)

--
David Rutten
david@mcneel.com
Poprad, Slovakia

Permalink Reply by Bas Goris on December 14, 2009 at 3:42pm

Thanks, I can go further. :)