Attractor point

Replies to This Discussion

Permalink Reply by David Rutten on March 1, 2012 at 12:35am

Hi Danny,

you need to insert an algorithm (technically a subroutine) between your Attractor-distance measurement and your extrusion length. You can use an expression to modify these numbers, for example:

E = 1000/d

Where E is the extrusion height and d is the distance from the attractor (if you put this into a F(x) component you only have to write 1000/d btw., the E = is implied). Do note that division like this may result in very high buildings, you might also want to add some protection against that.

Another approach entirely would be to use a Graph Mapper. Along the X axis you have your Attractor-distances, along the Y axis you'll have your Extrusion-heights. Then pick any graph you want to map between these scales.

--

David Rutten

david@mcneel.com

Poprad, Slovakia

Permalink Reply by Danny Andrés Osorio Gaviria on March 2, 2012 at 2:33pm

Hi David!!!...

It works!!!... you are a genius!!!...

Thank you very much for always be aware of all discussions in the forum... you are really helpful!!!...

Thanks again!!!...

Greetings from Colombia.

Danny.

Permalink Reply by Michael Pryor on March 11, 2012 at 5:07pm

you could also use remap component and remap the values for 1 to 0  to  0 to 1. inverting the distances proportionally.

Permalink Reply by konrad k sobon on November 11, 2012 at 8:20pm

David,

From your comment i understand that it's possible to extract x and y parameters from the graph mapper. Can you explain how i would need to go about it?

I am hoping to use an attractor point that will do two things for me:

        1. Based on its distance to a set of curves it will deform them in x and z directions away from the point. I want both of those deformations to be in a form of a gaussian curve thus graph mapper seems to be appropriate. How do i extract x and y so that they drive vector z and x?

thank you,

konrad