algorithmic modeling for Rhino
calculate the modulus (%) with Divisor 2. See if result is larger than 0. If so, A was odd, if not, it was even.
yeah ,a friend actually told me that just now. the fun thing is there is no need to compare the result, since it's either way 0 or 1, so you can use the output values directly from the modulus component, which is cool (and which is probably why there isn't a component that verifies even/odd numbers.. :)) )
Thanks for your answer!
just know your math and the shortcuts of programming ;)
It's funny isn't it? Computers divide by 2 and humans look whether the last digit is 0, 2, 4, 6 or 8. Another prime example of why it is so difficult to teach programming sometimes.
--
David Rutten
david@mcneel.com
Seattle, WA
In assembler times, when division took like 20 times longer than loading a number into the CPU, there used to be a way to load only the very last bit and interpret that as a boolean.
Instant even/odd
It probably still takes 20 times longer today...
--
David Rutten
david@mcneel.com
Seattle, WA
Maybe this could do the trick:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Runtime.InteropServices;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
for (int i = 0; i < 25; i++)
{
System.Collections.BitArray BA = new System.Collections.BitArray(new int[] { i });
bool[] BITS= new bool[BA.Count];
BA.CopyTo(BITS, 0);
Console.WriteLine(BITS[0]);
}
Console.ReadLine();
}
}
cheers Michael
Would love to see that compiled vs. the Modulus version...
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