Curve divided by number of division

Hi all,

I am facing a problem while trying to divide curves according to their curvature. It looks like I am iterating over the same points on each curve but I have been working for some time and my brain is frozen. If you have any suggestions or different ideas on how to divide a curve according to its curvature in C# please share.

Thanks in advance!

Double Scalefactor = -Factor;

for (int i = 0; i <crvList.Count; i++)

{

GH_Path Apath = new GH_Path(i);

GH_Path Bpath = new GH_Path(i);

////***Reparameterize each curve

Interval myint = new Interval(0, 1);

crvList[i].Domain = myint;

for (int j = 0; j < Divisions; j++)

{

Apath.AppendElement(j);

Bpath.AppendElement(j);

Point3d Point = new Point3d();

Vector3d Vec = new Vector3d();

Vec = crvList[i].CurvatureAt(j/Divisions);

Point = crvList[i].PointAt(j/Divisions);

A.Add(Point,Apath);

B.Add(Point + Vec*Scalefactor, Bpath);

}

Replies to This Discussion

Permalink Reply by David Rutten on December 5, 2012 at 5:09am

How does the curvature affect the division? What is the algorithm you'd like to see implemented?

David Rutten

david@mcneel.com

Poprad, Slovakia

Permalink Reply by Georios on December 5, 2012 at 7:36am

Hey David,

I found this piece of code online that seems to do what i want. The code is written in VB Legacy and I wanted to give it a shot to see if translating it into C# would work the same. I am attaching a Rhino file and a gh file. Again thank you for the great support!

Attachments:

Curvature Graph.3dm, 17 KB
Curvature Graph.gh, 4 KB

Permalink Reply by David Rutten on December 5, 2012 at 8:02am

Ok, that code generates a sort of CurvatureGraph, it doesn't do division of a curve based on curvature. I translated it into RhinoCommon C# (see attached).

David Rutten

david@mcneel.com

Poprad, Slovakia

Attachments:

CurvatureGraph.gh, 11 KB

Permalink Reply by Georios on December 5, 2012 at 9:08am

Thank you David,

I made a grasshopper definition as a pseudocode that I am step by step translating to C# to divide the curve based on its curvature and I think I am going with that one eventually. I wanted to see if this piece of code that I sent made sense to you. Again thank you for your time. I am sure I will bother you again during my translation. Thanks!!!

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