List Structure and Conditional statement

Hey Everyone,

I`m working on a deffinition based on attractors which make a surface "bend", my problem is that I need to be able to change the values of a list depending on the attractor`s action range, but without modifying the lists order:

suposing i have a structure list

(Paths = 75)

{0} (N = 51)

{2} (N = 51)

{3} (N = 51)

{4} (N = 51) ...............

I`m trying to apply to that list of values the statement:

if x>y then x=0

if x<y then x=x/z

but i need the list structure to keep exactly the same.

I`d be very thankful for any ideas on how to approach this problem.

Many thanks,

Roberto

Replies to This Discussion

Permalink Reply by trevor.patt on June 15, 2010 at 2:02am

In a VBscript component:
where x,y,z are inputs and a is an output:



If x > y Then a = 0

If x < y Then a = x / z

with none of the input variables set to list

or avoiding a script,
a) if you graft your data list first you can use a boolean pattern to separate the two conditions and when you recombine each value will still maintain its proper position
b) in this particular case you could cast a boolean to an integer (True becomes 1, False becomes 0) and then multiply against your second equation in a function component

Attachments:

list conditional.jpg, 241 KB

Permalink Reply by Roberto R. G. on June 17, 2010 at 9:19am

Thanks a lot Trevor!! I actually managed to solve partialy my problem using a weaveing pattern but it seems your solution fits better to what i`m looking for.
Cheers

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