Multiple Points / Finding the MINIMUM from 3+ inputs.

Hello again everyone!

I have a series of lofted fins, the length of which is determined by 2 attractor points.

These are based on a series of points, which take their distance relative to either point. The smaller (closer) value is then selected and used for the extrusion length. This is achieved with a simple 'MINIMUM'.

This works fine with only two points, but as I expand my model I'm going to need several more points. I've looked through other posts, but I can't find a clear way to have multiple numeric inputs (in this case, multiple measurements) of which the SMALLEST value is taken.

I'm looking for a little help so that I can add multiple attractor points to this definition. Please take a look? Thanks!

Attachments:

Replies to This Discussion

Permalink Reply by Michael Pryor on January 12, 2012 at 4:48pm

your in luck, david just invented an extremes component in the newest release, check it out.

Permalink Reply by Gwyll on January 12, 2012 at 5:49pm

what is the difference between the extremes component and the old max and min components?

Permalink Reply by Michael Pryor on January 12, 2012 at 6:09pm

extreme can accept infinite inputs, min and max can only do 2.

Permalink Reply by J. Pyeatt on January 12, 2012 at 7:45pm

Oh, sweet extremes...

I'll download and check it out momentarily !

Permalink Reply by J. Pyeatt on January 12, 2012 at 9:06pm

That worked wonderfully.

But there's always one more question. :)

Let's suppose that I now need to limit my inputs to a certain range. An if-then statement might work... but I don't let know how to create one in Grasshopper!

x = my input #

if x < 1.5; then use x...

if x > 1.5; substitute value 1.5

In essence, I need to limit the maximum length of a object to 1.5.

I can write this for you in another scripting language... but not this one!

Permalink Reply by J. Pyeatt on January 12, 2012 at 9:20pm

Oh, answered my own (dumb) question...

In a panel, plugged into a F(x)...

if(x<1.5,x,1.5)

Nice and straightfoward!

Thanks again for your help everyone!

Permalink Reply by Michael Pryor on January 12, 2012 at 9:30pm