Dividing a list into desired number of items.

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Permalink Reply by Han byul SEOL on May 7, 2011 at 5:26am

I just happen to solve the problem but I don't know how.. 

Could anyone please explain why this happened?

I'm still new at path mapper ... so i'm struggling.. 

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• path mapper problem-1.PNG, 145 KB

Permalink Reply by G on May 7, 2011 at 5:42am

{A;B}(i)......... {floor(i/ceiling(item_count/30))}

Permalink Reply by Han byul SEOL on May 7, 2011 at 6:11am

: ) thanks.. 

could you possibly explain me how come

{A;B}(i) --> {i/21} 

works differently?

Permalink Reply by Danny Boyes on May 8, 2011 at 4:30pm

/ is divide.

Therefore:

{0;0}(0) --> {0/21} = {0}

{0;0}(1) --> {1/21} = {0.048} = {0}

{0;0}(2) --> {2/21} = {0.095} = {0}

...

{0;0}(10) --> {10/21} = {0.476} = {0}

{0;0}(11) --> {11/21} = {0.524} = {1}

{0;0}(12) --> {12/21} = {0.571} = {1}

...

{0;0}(20) --> {20/21} = {0.952} = {1}

{0;0}(21) --> {21/21} = {1.0} = {1}

{0;0}(22) --> {22/21} = {1.0476} = {1}

...

{0;0}(628) --> {628/21} = {29.905} = {30}

{0;0}(629) --> {629/21} = {29.952} = {30}

 

Where as \ is integer divide. (Which is similar to Floor())

Therefore:

{0;0}(0) --> {0\21} = {0}

{0;0}(1) --> {1\21} = {0}

{0;0}(2) --> {2\21} = {0}

...

{0;0}(10) --> {10\21} = {0}

{0;0}(11) --> {11\21} = {0}

{0;0}(12) --> {12\21} = {0}

...

{0;0}(20) --> {20\21} = {0}

{0;0}(21) --> {21\21} = {1}

{0;0}(22) --> {22\21} = {1}

...

{0;0}(628) --> {628\21} = {29}

{0;0}(629) --> {629\21} = {29}

 

Permalink Reply by Han byul SEOL on May 9, 2011 at 8:08pm

oh!! thanks!!

Now I understand!! :) 

thank you!! :D