Replace Data Tree Addresses with new Addresses

Does anyone have a solution that does not involve scripting for the following problem:

I have two data trees with the exact same number of paths and items but with different addresses. For example:

Tree A

{0;0;0} N = 2

{0;0;1} N = 3

{0;0;2} N = 5

{0;0;3} N = 4

Tree B

{0;0;0} N = 2

{0;0;1} N = 3

{0;1;0} N = 5

{0;1;1} N = 4

I want the data in Tree A but with the path addresses in Tree B. Any ideas? I thought that ReplaceBranch would work, but it doesn't seem to be doing what I thought. There must be an easy solution that I am missing. Thanks.

Replies to This Discussion

Permalink Reply by Yoann Mescam (Systemiq) on April 28, 2011 at 6:18pm

This is perhaps what you want.

Permalink Reply by Yoann Mescam (Systemiq) on April 28, 2011 at 6:27pm

This works too, but I have the bad feeling I am missing something.

Permalink Reply by Stan Carroll on April 28, 2011 at 6:43pm

Hey Andrew,

I just learned how to do this with the help of Danny Boyles. The key is to use the param viewer component to build the mask from the source list.

I love your work by the way...been watching it for over a year.

Hope it helps.

Stan Carroll

Attachments:

Replace Branches Example.ghx, 91 KB

Permalink Reply by Yoann Mescam (Systemiq) on April 28, 2011 at 7:04pm

That is much better than my dubious solution !

Permalink Reply by Stan Carroll on April 28, 2011 at 7:09pm

Sorry, I meant Danny Boyes. Sorry Danny

Stan

Permalink Reply by Andrew Kudless on April 28, 2011 at 11:43pm

Thanks! That is exactly what I thought ReplaceBranch would do but for some reason I was entering the wrong combo of inputs (I had lots of weird wildcards in the mask). I knew there had to be an easy solution.

And thanks for the compliment!

RSS