How to create a polygone with angle of 30°

Replies to This Discussion

Permalink Reply by Birk Binnard on November 7, 2017 at 10:59pm

Do you mean a dodecagon?

Dodecagon

If that's what you want specify 12 sides for the Polygon component.

Permalink Reply by David Rutten on November 8, 2017 at 7:47am

There are three approaches that make sense to me, which one is best for you depends on what parts of this you want to be variable.

1. Just use the polygon component. You'll have to convert your desired angle into a segment count.
2. You can either start with a circle and divide it either into a integer number of segments (the corners of your polygon, but only if your corner angle divides 360 exactly), or into specific length segments for when you have a corner angle which doesn't fit neatly into 360 degrees. I guess the latter wouldn't really be a polygon since it wouldn't be fully symmetric, but maybe that doesn't matter in this case.
3. You can set up a range (or series) of angles, then create points using polar coordinates. This way you have a lot of control over both the angle per segment and the amount of segments, but it's a bit harder to figure out exactly how many segments you need for a fully closed polygon.

There's probably other ways as well, but you'll need to be more specific about what exactly you're after.

Permalink Reply by Daniel González Abalde on November 8, 2017 at 8:56am

Attachments:

• PolygonRegularFromLengthAndAngle.gh, 15 KB

Permalink Reply by Joseph Oster on November 8, 2017 at 9:25am

How do you get 14 sides instead of 12 with a 30 degree angle?

I used a formual found here: http://mathworld.wolfram.com/RegularPolygon.html

R = (a / 2) * csc(Pi / n) where 'a' = side length and 'n' = 360 / angle

I still don't know if this is what the OP is looking for?

Attachments:

• PolygonLengthAngle_2017Nov8a.gh, 15 KB

Permalink Reply by Daniel González Abalde on November 8, 2017 at 9:30am

woops, removing the NearestNumbers fixes it.