Graph Mapper curve division according to slope

Hello. I'm wondering if someone could help me out with this:

I have several curves with different slopes. I need to divide them according to their slopes from a linear graph to an exponential one.

That would mean that the curve with the smaller slope has to be divided in equals parts (linear) and that the curve with the bigger slope has to be divided in unequal parts (exponentially). The rest of the curves inbetween would be an interpolation of these concepts.

Then, it would be a sort of "range" for graph mapper from linear to exponential. How can I do this ?

Thank you !!

Attachments:

Graph Mapper Division Slopes.gh, 24 KB

Replies to This Discussion

Permalink Reply by David Rutten on February 18, 2017 at 12:11pm

Since you have an exact definition of your divisions already, I recommend not using GraphMapper but just a straight up equation. A bezier curve is not exponential btw.

What I would recommend is generating a bunch of numbers between zero and one. These will eventually be your division parameters, so the number of values needs to match the number of points you want. You'll end up with lists of numbers that looks like [0.0, 0.2, 0.4, 0.6, 0.8, 1.0].

You then process all the numbers using some equation. For example you could use a polynomial (which is not the same as exponential) x^n, where x is your numbers and n is some fixed value which depends on the slope. For a horizontal line you'd use n=1, for a slightly more inclined line x=1.1, etc. etc. The steeper the line the higher the exponent.

But you could also go for an n^x approach, which is exponential.

Permalink Reply by Fabrizio De Paolis on July 2, 2019 at 6:56am