Get sublayer full name in Grasshopper

Replies to This Discussion

Permalink Reply by Andrew Heumann on January 21, 2017 at 2:25pm

Layer.FullPath should do it. the ObjectAttributes component in human will also give you this information if you don't want to script. For the full script, taking in an object guid g:

var object = RhinoDocument.Objects.Find(g);

var attributes = object.Attributes;

var layerIndex = attributes.LayerIndex;

var layer = RhinoDocument.Layers[layerIndex];

var fullPath = layer.FullPath;

Permalink Reply by Nicholas on January 22, 2017 at 8:08am

Hello Andrew,

Thanks for your response. I tried to use ObjectAttributes component from Human. However, it still gives me the layer name where the object is in instead of the full layer name ( Default::Layer01::Layer02) Is it possible to get full path through ObjectAttributes ?

Also, I'm not sure if I did something wrong with the script you wrote, somehow I couldnt make it work.

Thanks again.

Nicholas

Permalink Reply by mire on January 23, 2017 at 10:39am

Hi Nicholas,

Look at the FP output of the ObjectAttributes component in your image. It is the Layer Full Path, which I think is what you are looking for

Permalink Reply by Nicholas on January 23, 2017 at 4:43am

Hello Andrew, do you know if there is a way to convert full layer name to object ID? I assume that the object ID also corresponds to the layer full name? 

Permalink Reply by Andrew Heumann on January 23, 2017 at 4:23pm

object id and layer full name have nothing to do with each other. you can have many objects with different ids on the same layer, so there cannot be a one-to-one mapping from layer full name to object id. Unless I am misunderstanding your question?

Permalink Reply by Joseph Oster on January 23, 2017 at 1:50pm

I found this (same as what you used?), with a working, modifiable C# component attached: http://www.grasshopper3d.com/forum/topics/access-to-the-attributes-...

Added 'path' output as follows, and managed to hack together a Python version as well.

C++ version:

int lIndex = doc.Objects.Find(guid).Attributes.LayerIndex;
Print(doc.Layers[lIndex].Name);
path = doc.Layers[lIndex].FullPath;

Python version:

import System.Guid as Guid
import Rhino
doc = Rhino.RhinoDoc.ActiveDoc
lIndex = doc.Objects.Find(guid).Attributes.LayerIndex
print doc.Layers[lIndex].Name
path = doc.Layers[lIndex].FullPath

Attachments:

• getLayer_2017Jan23a.gh, 7 KB

Permalink Reply by Nicholas on January 27, 2017 at 1:47pm

Hi Joseph, this is great! Thank you very much!!!