4 dimension (UVW)

Replies to This Discussion

Permalink Reply by David Rutten on December 26, 2015 at 11:57am

The answer to your previous (identical) question didn't satisfy?

http://www.grasshopper3d.com/forum/topics/difficult-mathematical-de...

Permalink Reply by Joseph Oster on December 26, 2015 at 2:35pm

Silly me...  warning, this is thread drift.

Before I looked at David's reply in the duplicate thread (so annoying!), which I don't understand anyway(?), I saw the "x=x+..." and thought "Oh, this is a series, I'll use Anemone" and hooked up a loop which is kind of interesting but looks nothing like the image in this post's question (at right).

It's just a series of concentric spirals, growing in size due to the loop.  I don't understand the reference to "w"...?

But it was fun as I learned more about Anemone in the process.

Specifically, I spent a lot of time trying to collect the list of points generated in each iteration as a partioned list, only to eventually realize I can get that easily using the 'Record Data' feature in Anemone's 'Loop End' component.  Wow, that's cool!

But again, I have no clue how these equations produce the image shown, which appears to be disk-like spirals around a sphere?

Show us how, Kenan?

Attachments:

• Spiral_2015Dec26b.gh, 18 KB

Permalink Reply by deniz ada on December 26, 2015 at 3:01pm

As it  can be seen,  good  definition.  I think I have  to use  Anemone Plugin.

Permalink Reply by Joseph Oster on December 26, 2015 at 3:26pm

It remains to be seen if it's a "good definition".  It's certainly not obvious yet. 

Oh, and PLEASE, no more duplicate threads!!

Permalink Reply by deniz ada on December 26, 2015 at 3:42pm

In fact. I try to create UK pavilion. This function belongs to it. But I cannot adapt your definition to this function.

u,v,w) 0 ≤ u ≤  2π    0 ≤ v ≤ π
0 ≤ w ≤  2π

Xo=sin(v)cos(u)
Yo=sin(v)sin(u)
Zo=cos(v)/(13/10)

Xw=sin(sin(Xo))
Yw=sin(sin(Yo))
Zw=sin(sin(Zo))

Attachments:

• uk pavilion.jpg, 6 KB

Permalink Reply by Joseph Oster on December 26, 2015 at 4:34pm

Follow David Rutten's lead, not mine.  The images you are providing are pretty terrible (small and fuzzy) but this one of the UK pavilion looks like what he posted two days ago when you asked this identical question in another thread:

http://www.grasshopper3d.com/xn/detail/2985220:Comment:1426067

Yep, looks like David's code got it - no surprise there: