Data Tree or List of List C#

Hi guys,

My plan is simple, I have data in a file that is arranged the following way(example):

1 2 3 4

5 6 7 8

9 10 11 12

I already extracted those data, now I want to put them in a tree so that the output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?

I have tried creating a tree and using a for loop to do so, but it didn't work.

Thank you for your help.

Replies to This Discussion

Permalink Reply by peter fotiadis on December 24, 2015 at 12:14am

Get these 2 (the first does what you want, the second is a bit more "fun" )

Attachments:

Integers_to_something_V1.gh, 9 KB
Dice_on_trees_V1.gh, 130 KB

Permalink Reply by Godjenka on December 24, 2015 at 12:59am

Thanks for your help!

Permalink Reply by peter fotiadis on December 24, 2015 at 1:05am

Oops forgot the other thing:

you want a List of List, int[,], int[][], matrix "options"? (only useful when doing things for usage outside the GH umbrella and therefor ... "skipping" DataTrees).

Permalink Reply by Godjenka on December 24, 2015 at 11:04am

I think it'll be ok, but for your first code, could you explain again why you have three cases? (I am new to programming)

Permalink Reply by peter fotiadis on December 24, 2015 at 11:38am

(a) The first option "groups" the integers (as Lists) into the tree.

(b) The second adds a second dimension so you have one item per branch (but still the "grouping" is intact: first dimension as on (a))

(c) The third adds a second dimension equal with the integer value (see (b) for the "grouping"):Of course has meaning(?) if the item type is integer.

Options added just to indicate 3 out of a myriad possibilities to sample items into trees.

Permalink Reply by peter fotiadis on December 24, 2015 at 11:52am

Of course the most "compact" (no options, intL etc etc) way is:

DataTree<int> intT = new DataTree<int>();
    int path = 0;
    for(int i = 0; i < count;i++){
      if(i != 0 && i % div == 0)path++;
      intT.Add((i + start), new GH_Path(path));
    }

Permalink Reply by Godjenka on December 24, 2015 at 1:13pm

Ok, thx!

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