Changing number character to another ?

Hi,

Do somebody know how to change characters of numbers to another ?

For example: List: From 341 342 343 344

To: 341 1 343 1

Any ideas ?

Miklos

Replies to This Discussion

Permalink Reply by David Rutten on May 30, 2014 at 6:23am

I don't get it, what's the logic behind the change?

David Rutten

david@mcneel.com

Permalink Reply by Pieter Segeren on May 30, 2014 at 6:37am

I guessed you meant to replace all even numbers with 1 ... :

Permalink Reply by Miklós Hatvani Deák on May 30, 2014 at 6:42am

Yes quiet, but actually to change numbers with last place-value of 6 (456,876,216..etc).

Where can i learn the usage of the comand "expression" ?

Permalink Reply by Danny Boyes on May 30, 2014 at 7:20am

Here and now is as good a time and place as any.

Expression is an instruction to do something that will return a value.

They crop up in GH in a few places as components [Expression] and [Evaluate] and also as an I/O Modifier.

If we take yours as an example. You want to see if a number ends with "6" and return 1 in its place if it does.

If we focus on the bold type in that statement you will see that already our expression is taking shape.

[IF] .... [NUMBER] ... [ENDS WITH "6"] ... [RETURN "1"]

as the correct syntax for the Expression Component is:

If(Endswith(x,"6"),1, x)

To break this down to more of an understandable level we have

an expression within an expression

The If Expression is If(TEST,A,B) which means that if TEST is TRUE return A, otherwise return B

and the Endswith expression is Endswith(s,a) which means that if the string s ends with "a" then be TRUE otherwise be FALSE

So our Endswith is our TEST condition in the If expression, the A is 1 and the B is our original value*

All the expressions available in GH can be found using the Button in the top right hand corner of the Expression Editor which looks like f:N=>R

* you should be aware that our original value has been converted to Text in order to work within this expression. If you need to keep the original number you may need to create a Boolean List of 1s and 0s to manipulate the original values elsewhere

Permalink Reply by Miklós Hatvani Deák on May 30, 2014 at 7:26am

It was really helpful, thank you !

Permalink Reply by Miklós Hatvani Deák on May 30, 2014 at 7:55am

I tried this but somehow every number are shown in my list exept the numbers with place value 6 at the end ? Why is this happening ?

Permalink Reply by Danny Boyes on May 30, 2014 at 8:02am

You're going to have to give me a little more than a statement of "it's not working".

Screenshot?

Definition?

Permalink Reply by Miklós Hatvani Deák on May 30, 2014 at 8:35am

Here is a screenshot...

Attachments:

prob1.png, 79 KB

Permalink Reply by Danny Boyes on May 30, 2014 at 8:48am

All of your strings have a zero at the end "1.0", "2.0", "6.0"

Try converting them to Integers by passing them through an [Int] Param

Permalink Reply by Pieter Segeren on May 30, 2014 at 7:21am

Ah, why didn't you ask for that in the first place?
See if this is what you want (I'm using a regex expression (.*6$) on the numbers (as text/string)):
the MatchText component can be found under Sets>Text.
If you open the Expression Editor/Designer, click on the last icon in the top row : f:N->R for the function list.

Edit: Danny's aprroach is much simpler, but if I recall correctly somebody already handed you that solution, so I tried sth different:)

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